I had hoped to find a calculator online for this... The wooden sheet on which my big reflector sits is beginning to deform at one of the corners where a caster goes. I want to replace this with something more durable before I have a catastrophic failure. So what thickness of steel do I need to support 150 pounds without too muh deformation? that chatgpt gave me this formula during a lucid, hopefully nonhallucinatory phase:
To calculate the maximum deflection of a rectangular plate supported at the four corners, you can use the classical plate theory (Kirchhoff-Love theory). For a rectangular plate under uniform load, the maximum deflection can be estimated using the following formula e:
where:
- is the uniform load per unit area (N/m²),
- is the shorter side length of the rectangular plate (m),
- is the flexural rigidity of the plate, calculated as:
In this formula:
- is the modulus of elasticity of the material (Pa),
- is the thickness of the plate (m),
- is the Poisson's ratio of the material.
Steps to Calculate Maximum Deflection:
- Determine Material Properties: Find the values for and for the plate material.
- Calculate Flexural Rigidity : Use the thickness of the plate.
- Define Loading Conditions: Determine the uniform load and the dimensions of the plate.
- Apply the Formula: Substitute the values into the formula to find .
The load is not centrally located but this seems a worst case assumption. The casters at the four corners of the current 28" plywood square are not sitting at the true corners of course but close.
load = 150 pounds / 2.2 * 9.8 giving 668N/m^2 (okay the load is not the same eveywhere but this is an approximation)
a = 28 inches/39.37
thickness is .25 inches /39.37
E is 200 GPa for steel
v is Poisson's ratio, which all examples seem to regard as .3
D calculates as 4385.9
maximum deformation is .04 m or about 1.5 inches.
This seems absurdly high for 1/4" steel plate. The plywood sheet there right now is not eforming that much. Do you see what I am doing wrong?
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